Algebra!
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11 Jan 2009, 20:28
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Journals
Prove that the transformation T is lineair and determine the matrix of T compared to the standardbasisses if T is the image of R^3 to R^5, defined by T(x,y,z)=(x,y,x+z,y,z)
I got your respect now?
12hours till exam, of which I'll sleep 5!
Serious business and stuff ;o
How long does crossfire sleep before an exam?
I usually sleep ~7 hours at a normal night, last exam I only did like 4 hours, which was too little.
+My cat ran away from my room, I need his support :(
me and my cat this afternoon:
I got your respect now?
12hours till exam, of which I'll sleep 5!
Serious business and stuff ;o
How long does crossfire sleep before an exam?
I usually sleep ~7 hours at a normal night, last exam I only did like 4 hours, which was too little.
+My cat ran away from my room, I need his support :(
me and my cat this afternoon:
i normally sleep about 8hours which is definitely too little on exams day too :/
Luckily I passed all my maths at uni already and don't need to think about this stuff anymore x)
Good luck with your exams!
T(a*(x,y,z))=(ax,ay,az) = (ax,ay,ax+az,ay,az) = (ax, ay, a(x+z), ay, az) = a * (x,y,x+z,y,z) = a * T(x, y, z)
Normally i sleep a bit less than 6 hours a night be4 exam.
Gl
(1,0,1,0,0)
(0,1,0,1,0)
(0,0,1,0,1)
long way to come there:
(a1.a2.a3)...........(x)
(b1.b2.b3)...(x)....(y)
(c1.c2.c3).*.(y).=.(x+z)
(d1.d2.d3)...(z).....(y)
(e1.e2.e3)...........(z)
=>
a1 = 1
a2 = 0
a3 = 0
b1 = 0
b2 = 1
b3 = 0
c1 = 1
c2 = 0
c3 = 1
d1 = 0
d2 = 1
d3 = 0
e1 = 0
e2 = 0
e3 = 1
so u get ur transformationsmatrix, and compare this to basis vectors.
http://img147.imageshack.us/img147/9017/dsc06151hv6.jpg
You had to learn this recently aswell?
If it's some years ago you're quite smart ;/
What do you do/study?
Dno if its called the same in germany :>