cf need ur help again MATH :)
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29 Jan 2012, 19:34
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Journals
In 2 weeks I got final exams in math thats why I am learning it everyday. But now I have a problem
well I have this function f(x)=(40*e^x)/(1+e^x) and i need the turning point, so I have to do the 2nd differentiation f''(x)=(40*e^x)/(1+e^x)^4 thats right or?
for the turning point must be 40*e^x=0 so x=??? for me its not possible because e^x cant be 0 or am I wrong?
thx2everyone who try to help me much love<33333
well I have this function f(x)=(40*e^x)/(1+e^x) and i need the turning point, so I have to do the 2nd differentiation f''(x)=(40*e^x)/(1+e^x)^4 thats right or?
for the turning point must be 40*e^x=0 so x=??? for me its not possible because e^x cant be 0 or am I wrong?
thx2everyone who try to help me much love<33333
/exec cancer
:DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
<33333333333
solution:
0=-1+e^x <=> 1=e^x => x=0
danke :) ich glaube es ist jetzt genug nach 8std lernen schwindet die konzentration allmählich^^