Can someone find the derivative of this shit?

by Gibri • 30 Oct 2006, 22:46 • Journals
y = ln((e^x - e^-x)/(e^x+e^-x))
Comments
12
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swas 30 Oct 2006, 22:50
the awnser is T
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evan 30 Oct 2006, 22:51
I could it you wrote it down propely.
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N30 30 Oct 2006, 22:55
wish i could still do that :o
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wipeout 30 Oct 2006, 23:01
cba to calc it myself, so here is what derive said:
4·e^(2·x)·LN(e)/(e^(4·x) - 1)
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Gibri 30 Oct 2006, 23:06
<3

can you also do y = ln((e^x+e^-x)/(e^x-e^-x))

<3 edit it was / not - as i had written :s
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wipeout 30 Oct 2006, 23:14
4·e^(2·x)·LN(e)/((e^(2·x) + 1)·(1 - e^(2·x)))
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Whitey 30 Oct 2006, 23:16
gotta learn this crap for January:@
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swas 30 Oct 2006, 23:31
Brainless 5days a week working and earning allot of money > school.
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antalis 30 Oct 2006, 23:32
i could but i cba
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slappa 31 Oct 2006, 07:11
got my exam for this crap on friday and monday (in the middle of long weekend here in australia :<)
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