deleted math journal,
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9 Nov 2010, 22:54
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Journals
some guy posted random math problem and i saw a lot of idiots in that topic
so... the problem was:
a^2-6a+9
-------------
a^2-9
as far i remember from my school times its:
a^2-6a+9 = (a-3)^2
a^2-9 = (a-3)(a+3)
makes it:
(a-3)
-------
(a+3)
am i right???
so... the problem was:
a^2-6a+9
-------------
a^2-9
as far i remember from my school times its:
a^2-6a+9 = (a-3)^2
a^2-9 = (a-3)(a+3)
makes it:
(a-3)
-------
(a+3)
am i right???
My advice : less gaming more school.
The expression a^2-9 = (a)^2 -(3)^2 = (a+3)(a-3)
so the given expression becomes
((a-3)^2)/((a-3)(a+3))
son one (a-3) is cancelled
(a-3)/(a+3)
Binomic theorems needed:
(a-b)^2 = a^2 - 2ab + b^2
a^2 - b^2 = (a-b) * (a+b)
a = -3
-3 -3 = -6
-3 x -3 = 9
e: also, u dont even need to include the 'x' :)
omg so easy!
a²-3a³+a²=4
2a²-3a³=4
-23a=4
a=-19
a²-a²-6a = -6+9
3 = -a²-6a
Now she's stuck ;O
-6a=3
a=-1/2