Stats q.
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13 Nov 2006, 00:33
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Journals
Stuck @ a question and need to know how to do it for tomorrow =x
Normal distribution with mean -3 and standard deviation 4 to find the required values of x.
Normal distribution with mean -3 and standard deviation 4 to find the required values of x.
Laplace transforms I can do, double integrals I can do, statistics no.
normalcdf(a,b,c,d) explained:
a = left border
b = right border
c = average (normal distribution)
d = standard deviation
use your calculator for this.
mu = -3
x1 = 3
x2 = 6.5
x2 > x1
for x1:
Z1 = (3 -(-3))/4 = 6/4 = 3/2 = 1.5
for x2:
Z2 = (6.5 -(-3))/4 = 9.5/4 = 2.375
P1 = 0.933
P2 = 0.9911~
P2 - P1 = 0.9911 - 0.933 = 0.0581
hope i didnt get anything wrong
since space on the graph = probability, removing P1 (stuff left of the smaller value) from P2 (stuff left from the higher value) makes sense
math ftw
(this is assuming you need the probability, which is probably what the question is asking u for..)
Edit: are you some kind of pedofile math teacher with no life?
A Math Community
i was tired, lets just say that :D