mathematiczZz 2
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17 Nov 2006, 18:59
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Journals
1
11
21
1112
3112
211213
So what i need is the number which comes under 211213 , with explanation plz <3 Thx!
11
21
1112
3112
211213
So what i need is the number which comes under 211213 , with explanation plz <3 Thx!
Following this pattern, the next 5 numbers are:
{...312212, 213223, 113223, 212223, 114213, ...}
There are 3 ones, 2 twos and 1 three in the previous line, hope you can see the pattern.
You've got 211213 in the last line you wrote. In this line you have three ones (on second, third and fifth position), two twos (1st and 4th) and one three (6th). Using this information, you create the next element of the sequence, presenting the number of particular digits in the previous element. Hence, you have 31 (three ones), 22 (two twos), 13 (one three), which gives 312213.
just count the number of "1" from the previous number; the rest is pretty clear
geef als antwoord 1337 dan is t altijd goed
think so
EDIT1: Then you need to put it in some kind of order: like first the 1's, then the 2's and then the 3's
EDIT2: You need to put the double numbers in first (before my EDIT 1 :P )
EDIT3: now it's weird :/
11
21
1112
3112
211213
312213
212223
114213
31121314
41122314
31221324
21322314
21322314
... Converge
132112
1113122112
311311222112
13211321322112
How the hell did you end up with the sequence you have? :x
Could be your way tho, both cud be the algorithm they are looking for.
Who knows.
21
1112
3112
The first line has one 2, and one 1. The next bit in the sequence we got taught at school for no apparent reason would be 1211, because you count from left to right and that's basically what it says. The next line in their sequence however, goes from right to left for a reason I don't understand. The third however, goes from left to right again.
Perhaps I'm missing an obvious pattern, but it's just different from what I've seen before. :o)
haha
112317
31121317
41122317
3122131417
4122231417
3132132417
3122331417
3122331417
... Converge