1337 oclock
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15 Jun 2011, 13:37
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Bitches.
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EDIT: So hey I just installed Brink (skidrow ofc) pretty crap isnt it?
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EDIT: So hey I just installed Brink (skidrow ofc) pretty crap isnt it?
het is trouwens butanAl en niet butanOl
will check it by literature
e : checked now the literature.
if the ethanol is stoichiometric, a hemiacetal is formed.
if the ethanol is in excess, an acetal is formed.
so here I would say an acetal is formed.
brb
So after reading I think that this should be the answer:
Butanal ->(reduction) forms an alcohol
so then we just have ethanol + the formed alcohol wich will make an ether since we are working in an acid solution
I guess that's how it works?
what I dont get is the "butanal -> (reduction)" part. If an aldehyde is treated with a nucleophile it becomes an alcohol (reduced version), BUT it is not reduced if the nucleophile is an O-nucleophile, because the oxidation number is depending on the substituents attached to the carbonyl-C. if a double bond to an oxygen atom is transformed to two single bonds to two oxygen atoms, the oxidation number doesnt change.
In your example, there is no reducing agent present and when the acetale is formed it should have the same oxydation number on the "carbonyl"-C than before.
e: I can post the mechanics of the reaction if you like :)
http://www.youtube.com/watch?v=jkCyLCazTpQ&feature=player_embedded
derp :|
Posted by h20xyg3n on Wednesday 15th June 2011, 12:37 GMT