quickQuiz #2 (maths or PC)
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20 Nov 2007, 20:51
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Journals
A. Compute (or state, if you already know it) the limit when N->infinity:
(1+1/N)^N
I'm trying to find a nicer one in the mean-time :)
Second try:
B. Find the limit when N-> infinity:
1+1/2+1/3+1/4+....+1/(N-1) - ln N
where ln N is the logarithm whose base is the number you've calculated in A.
(1+1/N)^N
I'm trying to find a nicer one in the mean-time :)
Second try:
B. Find the limit when N-> infinity:
1+1/2+1/3+1/4+....+1/(N-1) - ln N
where ln N is the logarithm whose base is the number you've calculated in A.
i see i have to find more difficult stuff when you're around :)
y^infinity = 0 for 0<y<1
y^infinity = infinity for 1<y
Thus, 1^infinity is undefined.
B = Limit = gimme 1 sec
i think that B is divergent or convergent dnno xD forgot it ( i think it means that there is no limit)
1+1/2+1/3+1/4+...1/N-1 is divergent... but after subtracting natural logarithm of N you get convergent
= no limit
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+ i dont understan this sentence
where ln N is the logarithm whose base is the number you've calculated in A.
... sum = 0
... for i in range(1,n):
... sum += 1.0/i
... print sum - math.log(n)
>>> calc(2000000)
0.577215414901
And ln n is logarithm in base e...
>>> math.e
2.7182818284590451
cuz im good in math xD
Puu told meh :O
0.577215
I go to ze store.. its closed..
Then i go back home, i stepped in dog sh*t..
How many apples do i have?