Chemistry help please

Need help with these two question's cant remember back to my chemistry days

1) Whats the concentration of a solution of NaOH 25cm3 of which requires 20cm3 of HCL 0.1 mol dm-3 to neutralise

2) Sodium carbonate Na2Co3 is used of concentration 0.1 mol dm-3 to neutralise HCL 25cm3 of Na2Co3 solution requires 35cm3 of the acid to neutralise. Calculate concentration of the acid.

could you plz kinda explain how to do them
Comments
15
no binas no win
2 much to write, soz :(
1. There's as much NaOH as there's HCL. That means the concentration of NaOH is (20cm3*0.0001mol/cm3)/25cm3 mol/cm3 if I'm not mistaken.
2. For CO3¯, look up it's acid constant (or whatever, never did this in english :S) and do the calculations i've forgotten how to do :D

No chemistry for 2 years, don't shoot me if it's wrong..
im going to shoot you if its wrong
Parent
ask perfo
Fairly easy, but I don't have time to explain - google ftw!
i should be able to do it, but i forgot everything :>
use your books.
All science is either physics or stamp collecting.

in before shitstorm.
I hated chemisty even though I wasn't that bad at it :/
no brain no gain
1) I agree with plekter
2)is there some Ka or pKa given ?

edit : you can use this formula K=([products1]^coeffstoec1*[products2]^coeffstoec2)/([reactant1]^coeffstoec1...) ect

and i can't see any solution if theres no K Ka or pKa given

edit2: it's really easy just convert the concentration in amount of mol n=C*V then n na2co3=n Hcl and CHcl is not known => neutralization of na2co3 by the acid

i just start a chemistry school this year

you really have to learn n= C*V and equivalence = neutralization otherwise you will just faillll
Saw that last year

Requires thinking => sorry :(
try learn some basic principles, otherwise you will fail hard
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