Algebra
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1 Dec 2008, 01:15
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Journals
ehh im confused in my book it says
Expand these expressions
2(3.+m)
5(2+1)
3(2-4f)
i suck at algebra so can someone explain please? :<
Expand these expressions
2(3.+m)
5(2+1)
3(2-4f)
i suck at algebra so can someone explain please? :<
->
2 ( 3 . + m )
I KNOW IT'S OLD
2(3+m) = (2*3) + (2*m) = 6+2m
5(2+1) = (5*2) + (5*1) = 15
3(2-4f) = (3*2) - (3*4f) = 6-12f
Hope that helps.
first you solve whats in the ()
dont do the same mistakes as panda did !!!!!!!!!!!
2+2*2
anyway its 6...
but if u have something to add up in () it doesnt matter if u solve the stuff inside the () first or if u do it like he did....
but if u have to multiply u should solve the () first ;]
THERE ARE RULES
DOESNT MATTER ITS THE SAME OUTCOME
YOU SOLVE THE () FIRST !!!!!!!!!!
anyway panda said its 8 :DDDDDDDDDDDDDD
he will ignore it in the future :(
french
fuck you jew die irl in a cashfire
G-line !!!
18/(3+3) = 18/6 = 3
However, in my case it is perfectly correct to distribute the 5 because that's how you do expansion properly... Expansion is a rule which works in math and when you use you always get the right answer. Trust me, I know what I'm talking about :)
By the way, your example is completely relevant. You are discussing brackets yet you provide an example with NO brackets to be found anywhere, good job :D
2+2*2 is an instance of multiplication before addition in the order of operations...
sry if you misunderstood me :(
in hebrew its a fact D:
you must follow the rules :DDD
5(2+1) =>5*2+5*1=15
3(2-4f)=>3*2-12f=6-12f
Liar.
(k) ° (7) = 0
(3) (k)
for what k is this term = 0 ?
vector etc. btw.
and ° = skalar
just wanted to post somethin^^