Math help thx
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20 Jan 2011, 02:23
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Lim h -> 0
(x+h)^3 - x^3/h
Pls help :( or ill fail exams
(x+h)^3 - x^3/h
Pls help :( or ill fail exams
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35.2 %
(19 votes)
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64.8 %
(35 votes)
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(x+0)^3 - x^3/0 =
x^3 - endless
so if x is a random number, ur answer is - endless
so x will be a real number imo
-infinity IF ( x< 0 )
might be wrong, no time to think about it :D
then u have a look at x^3/h : h becomes smaller and smaller , until it ALMOST reaches 0 , so the term x^3/ h becomes bigger and bigger.
( lets say x^3 is a normal number e.g. 12 . 12/12 = 1 ( h = 12 in this case )
12/6 = 2
12/3 = 4
12/ 1,5 = 8 and so on -> so if h becomes smaller and smaller , x^3/h becomes bigger and bigger !
all in all u have a look at the results which are : x^3 MINUS infinity = - infinity.
thats for x > 0
but if x is < 0 the second term ( x^3/h becomes smaller and smaller, because 3 is an uneven number ( for example -2^3 = -8 )
so the result for x<0 is x^3 MINUS MINUS ( = PLUS ) infinity = infinity
I have 5 hours to learn and practice 12 weeks worth of calculus. Any suggestions?
Cry.
Usually if I get to it 1 week before the exam or deadline, I can manage.
But 5 hours is a lost cause :)
then u sub. in (x+h) for the x's + put it all over 'h'
then u simply expand the brackets and simply?
u dont need to know more
The solution:
lim (x+a)^3 - x^3/a = x^3 - x^3/0 = x^3 - infinite = -infinite
If x is infinite, then you got an exception case: infinite - infinite. The solution to this case is the world wide web. :)
Haven't done limits for like 3 years now, still nice. :D
ik had de gele versie
keb eco al bijna af en tis al :p
gij?
vo de rest van alle vakken wel al iets gdaan ma ng nie egt ver geraakt :/